# A PHOTON HAS A FREQUENCY OF 5.02 X 10^14 HZ, CALCULATE THE ENERGY OF THE PHOTON IN JOULES AND ELECTRON VOLTS

*(i) To calculate the energy of a photon in joules, we can use the formula:*

**E = hf**

Where E is the energy of the photon, h is Planck’s constant, and f is the frequency of the photon.

**Given: **

**Frequency (f) = 5.02 x 10^14 Hz **

**Planck’s constant (h) = 6.6 x 10^-34 Js**

Substituting these values into the formula, we get:

**E = (6.6 x 10^-34 Js) * (5.02 x 10^14 Hz) **

**E = 3.3132 x 10^-19 J**

Therefore, the energy of the photon in joules is approximately **3.3132 x 10^-19 J.**

*(ii) To calculate the energy of a photon in electron volts (eV), we can use the conversion factor:*

**1 eV = 1.6 x 10^-19 J**

Given that we already calculated the energy of the photon as approximately **3.3132 x 10^-19 J**, we can convert this to electron volts by dividing it by the conversion factor:

**E(eV) = (3.3132 x 10^-19 J) / (1.6 x 10^-19 J/eV)**

** E(eV) ≈ 2.07075 eV**

Therefore, the energy of the photon in electron volts is approximately **2.07075 eV.**