A TRANSPARENT RECTANGULAR BLOCK 5.0CM THICK IS PLACED ON A BLACK DOT. THE DOT WHEN VIEWED FROM ABOVE IS SEEM 3.0CM FROM THE TOP OF THE BLOCK, CALCULATE THE REFRACTIVE INDEX OF THE MATERIAL OF THE BLOCK

• A. 2/5
• B. 3/5
• C. 3/2
• D. 5/3 ✓
• E. 5/2

 

The answer to the question is: D. 5/3

To calculate the refractive index of the material of the block, we can use the concept of apparent depth. When a transparent block is placed on a black dot, the dot appears to be shifted due to the refraction of light as it passes through the block. The apparent shift in the position of the dot can be used to determine the refractive index of the material.

The formula for calculating the refractive index using apparent depth is:

n = real depth/apparent depth

Where:

n = refractive index

real depth = actual thickness of the block

apparent depth = apparent distance of the dot from the top surface of the block

Given:

real depth (thickness of the block) = 5.0 cm

apparent depth (distance of the dot from the top surface) = 3.0 cm

Using the given values in the formula:

n = 5.0 cm / 3.0 cm

n ≈ 5/3 or 1.67

Therefore, the refractive index of the material of the block is approximately 1.67.